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D( x )
x-3 = 0
x-3 = 0
x-3 = 0
x-3 = 0 // + 3
x = 3
x in (-oo:3) U (3:+oo)
(x^2-5)/(x-3) = 0
1*x^2 = 5 // : 1
x^2 = 5
x^2 = 5 // ^ 1/2
abs(x) = 5^(1/2)
x = 5^(1/2) or x = -5^(1/2)
x in { 5^(1/2), -5^(1/2) }
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